Question ：

Given a binary tree, find its minimum depth.

The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.

Anwser 1 ：

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    int minDepth(TreeNode *root) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        if (root == NULL) return 0;
        
        int left = minDepth(root->left) + 1;
        int right = minDepth(root->right) + 1;
        
        // leaf
        if (left == 1 || right == 1)
            return left > right ? left : right;
            
        return left < right ? left : right;
    }
};

Anwser 2 ：

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    int minDepth(TreeNode *root) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        if (root == NULL) return 0;
        
        int depth = 1;
        queue <TreeNode *> current;
        queue <TreeNode *> next;
        current.push(root);
    
        while (!current.empty())
        {
            while (!current.empty())
            {
                TreeNode *n = current.front();
                current.pop();
                if (n->left==NULL && n->right == NULL) return depth;
                if (n->left) next.push(n->left);
                if (n->right) next.push(n->right);
            }
            
            queue <TreeNode *> t;   // init queue
            current = next;
            next = t;
            depth += 1;
        }
        return depth;
    }
};